This statistic is a useful and simple measure. Many times in MR, we want to know if a proportion is equal to one expected, or if proportions from different samples are equal.
For example, suppose that a client says that he will only manufacture a new product if more than 60% of respondents say they will buy it. A sample of 500 people is selected. When the data is analyzed, it is found that 62% said they would buy the product. Is the client safe in making a decision to build the product?
The statistic looks like this:

Where p = the hypothesis tested, in this case p = .60, po= .62, and q = 1 – p, and n = 500.
Z then is equal to 0.913. Go to the statistical appendix of a MR or statistical text and find the first table, then look up the value of Z = 0.91 (or look up the value of Z on the net). It is equal to 0.8186. Subtracting this value from 1.0 equal “sig.” So “sig” is equal to 1 - .8186 = 0.1814. We are still looking for “sig” less than .05. Therefore we would tell our client that there is no evidence that “more than” 60% will buy his product.
Z can also be used to compare two groups. Suppose that a researcher took a sample of
200 students from both ISU and one from

Where p1 = .70 and p2 = .75, and p = (f1+f2)/(n1+n2) or (140 + 150)/(200 + 200) = .725, and q = 1 – p.
Z in this case is equal to –1.12.
Sig is 1 - .8686 =
0.1314. We do not have enough
evidence to say that ISU and
What to do?
This test does not exist on
Do the following:
Show all work (handwritten). Show all answers (typed).
1. A coin is thrown 200 times, is it a fair coin if it comes ups heads 58% of the time?
2. A sample of 1000 people found that 38% supported a new tax. The supporters said they would pursue the tax only if 35% supported it. Should they proceed?
3. A die is thrown 72 times, the face with a two showed up 19 times, is the die fair?
4. In
5. A random sample in Waterloo found that 70% supported a new sales tax for education. Only 65% of the people in Cedar Falls supported it. Are the two populations different? The Waterloo sample was of 300 people, the Cedar Falls sample was of 100 people.